Pr(A)=0.16
Only two alleles are presented. Then, 
the frequency of the allele B is 1 - Pr(A) = 0.84

According to Hardy-Weinberg principle,
Pr(AA)=Pr(A)*Pr(A) = 0.16 * 0.16 = 0.03
Pr(AB)=2*Pr(A)*Pr(B) = 2 * 0.16 * 0.84 = 0.27
Pr(AA)=Pr(B)*Pr(B) = 0.84 * 0.84 = 0.70