Pr(A)=0.36
Only two alleles are presented. Then, the frequency of the allele B is 1 - Pr(A) = 0.6379

According to Hardy-Weinberg principle,
Pr(AA)=Pr(A)*Pr(A) = 0.36 * 0.36 = 0.13
Pr(AB)=2*Pr(A)*Pr(B) = 2 * 0.36 * 0.64 = 0.46
Pr(AA)=Pr(B)*Pr(B) = 0.64 * 0.64 = 0.41